Homework tonight is 3 ACE 21-26, 43 DUE ON TUESDAY 11/20/07.
Make sure you are writing down the original problem and showing how to solve.
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34 comments:
i dont really understand how 2 do # 43 a...
can u help mee?
rockersquirrel,
Factor 48t-16t^2. From there set each factored part equal to zero. Solve each for t. This will help you determine how many seconds (t) the ball will be in the air for.
but i dont really get how 2 factor this type of equation...
can u give me an example on how 2 solve this?
rockersquirrel,
Look at the two terms
48t and -16t^2
what can you factor out?
the 48t and the 16t^2?
what i did was t(-16t+48)
to get t=0 t=3
but 0 - 3 = -3...
rockersquirrel,
yes.
okay you got your two solutions,
t=0, t=3
what's with 0-3 = -3?
r u supposed to add the 2?
no. When you set each factored part equal to zero and solve those are your two solutions. Based on your two results, what would be the amount of time (t) that the ball is in the air?
do u have to replace t with the 2 solutions?
48(0)-16(3)^2
or...
x=0 + x=3?
oooooooooohhhhhhhhhhhhhhhhhhh!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
i get it!
technically you solved for t. So of the two, t=0 and t=3, which makes sense?
t=3...right?
right, because if it were t=0, the ball would have gone nowhere.
so for b, u have to replace BOTH t's with 3, or no...
y do they always have to use t? it always looks like a plus
in my tablet...
when choosing variables they usually use the first letter of the word. t = time, d= distance, etc.
thatz wierd....48*3=144 and 16*9=144...so then it wouldnt even get off the ground...strange...
do u have to replace h with 30?
u do, dont u...or would u get the same answer, hmm....
i dont understand how to get the answer 4 43.b....
do u have 2 do dubble step?
i dont get it...
I'm trying to figure out what the book did to get the answer that it says for part b.
Okay, I'm trying to make sense of this. If the ball is in the air for 3 seconds, meaning it bounces up and comes back down in 3 seconds. After how many seconds (within these 3 seconds) does the ball come back down. I guess what I mean is how many seconds does it take to bounce up and how many seconds does it take to bounce down so you get a total of 3 seconds.
can u specify what u would like me to do?
so you know it takes 3 seconds to go up and come back down. After how many seconds is it at the highest point?
so does it get to 30 ft. in 1.5 sec.?
okay, you figured out that it's 1.5 sec. Substitute this into the original equation by replacing t with 1.5 and solving for h.
THANK U SO MUCH!!!!!!!!!!!!
your welcome. If there's a question on this problem tomorrow, your teaching it. Good night.
good night!
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